Choose: < output >
In order to maximize: < profits >
π(q)=R(q)−C(q)
Graph: find q∗ to max π⟹q∗ where max distance between R(q) and C(q)
π(q)=R(q)−C(q)
Graph: find q∗ to max π⟹q∗ where max distance between R(q) and C(q)
Slopes must be equal: MR(q)=MC(q)
π(q)=R(q)−C(q)
Graph: find q∗ to max π⟹q∗ where max distance between R(q) and C(q)
Slopes must be equal: MR(q)=MC(q)
At q∗=5:
Suppose the market price increases
Firm - always setting MR(q)=MC(q) - will respond by producing more
Suppose the market price decreases
Firm - always setting MR(q)=MC(q) - will respond by producing less
The firm's marginal cost curve is [mostly] its (inverse) supply curve Supply=MC(q)
There is an exception to this! We will see shortly!
Profit is π(q)=R(q)−C(q)
Profit per unit can be calculated as: π(q)q=AR(q)−AC(q)=p−AC(q)
Profit is π(q)=R(q)−C(q)
Profit per unit can be calculated as: π(q)q=AR(q)−AC(q)=p−AC(q)
Multiply by q to get total profit: π(q)=q[p−AC(q)]
At market price of p∗= $10
At q∗=5 (per unit):
At q∗=5 (totals):
## geom_segment: arrow = NULL, arrow.fill = NULL, lineend = butt, linejoin = round, na.rm = FALSE## stat_identity: na.rm = FALSE## position_identity
At market price of p∗= $10
At q∗=5 (per unit):
At q∗=5 (totals):
At market price of p∗= $10
At q∗=5 (per unit):
At q∗=5 (totals):
At market price of p∗= $10
At q∗=5 (per unit):
At q∗=5 (totals):
At market price of p∗= $2
At q∗=1 (per unit):
At q∗=1 (totals):
At market price of p∗= $2
At q∗=1 (per unit):
At q∗=5 (totals):
At market price of p∗= $2
At q∗=5 (per unit):
At q∗=5 (totals):
At market price of p∗= $2
At q∗=5 (per unit):
At q∗=5 (totals):
What if a firm's profits at q∗ are negative (i.e. it earns losses)?
Should it produce at all?
Suppose firm chooses to produce nothing (q=0):
If it has fixed costs, its profits are:
π(q)=pq−C(q)
Suppose firm chooses to produce nothing (q=0):
If it has fixed costs, its profits are:
π(q)=pq−C(q)π(q)=pq−f−VC(q)
Suppose firm chooses to produce nothing (q=0):
If it has fixed costs, its profits are:
π(q)=pq−C(q)π(q)=pq−f−VC(q)π(0)=−f
π from producing<π from not producing
π from producing<π from not producingπ(q)<−f
π from producing<π from not producingπ(q)<−fpq−VC(q)−f<−f
π from producing<π from not producingπ(q)<−fpq−VC(q)−f<−fpq−VC(q)<0
π from producing<π from not producingπ(q)<−fpq−VC(q)−f<−fpq−VC(q)<0pq<VC(q)
π from producing<π from not producingπ(q)<−fpq−VC(q)−f<−fpq−VC(q)<0pq<VC(q)p<AVC(q)
π from producing<π from not producingπ(q)<−fpq−VC(q)−f<−fpq−VC(q)<0pq<VC(q)p<AVC(q)
Firm's short run (inverse) supply:
Firm's short run (inverse) supply:
1. Choose q∗ such that MR(q)=MC(q)
1. Choose q∗ such that MR(q)=MC(q)
2. Profit π=q[p−AC(q)]
1. Choose q∗ such that MR(q)=MC(q)
2. Profit π=q[p−AC(q)]
3. Shut down if p<AVC(q)
1. Choose q∗ such that MR(q)=MC(q)
2. Profit π=q[p−AC(q)]
3. Shut down if p<AVC(q)
Firm's short run (inverse) supply:
{p=MC(q)if p≥AVCq=0If p<AVC
Example: Bob's barbershop gives haircuts in a very competitive market, where barbers cannot differentiate their haircuts. The current market price of a haircut is $15. Bob's daily short run costs are given by:
C(q)=0.5q2MC(q)=q
How many haircuts per day would maximize Bob's profits?
How much profit will Bob earn per day?
Find Bob's shut down price.
Write Bob's short-run inverse supply function.
Choose: < output >
In order to maximize: < profits >
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